How to pass variable by reference in php ?

Hello Everyone, I try to pass variable reference in method but variable reference are not pass in method.
Please help me for that.
My code is below :-

Code:

<?php

$b=10;
$a=5;

method_A($a);
method_b($a,$b);

function method_A($var1)
{
    echo $var1++ . "\n";
}

function method_b($var1, $var2)
{
    echo $var1++ . " And " . $var2++;
}

?>

Advance Thanks.

 

Hi
For passing reference of a variable you have to use & sign in method parameter. Find below code. i have modified your code.

Code:

<?php

$a=5;
$b=10;

method_A($a);
method_b($a,$b);

function method_A($var1)
{
    echo  "a before: " . $var1++ . "\n";
}

function method_b(&$var1, $var2)
{
 $var1 = 10;
    echo "a After changing it value to 10: \n" . "a: " . ++$var1 . " And b:" . $var2++;
}
?>

Here, i have passed reference of $a variable to the function_method_b. Then i changed $a's value to 10. so output of $a is now 10. and output of $b will be as it is because i didn't changed that value.
Hope this will help you.
Thank you.